Beginning Algebra Workshop
Solutions to Exam 1
50 points
Problems 1-15 are worth 2 points each. Give the correct answer:
|
1) -4 - (-23) = -4 + 23 = 19 |
8) Solve: x - 12 = -18 |
||
|
x x |
= -18 + 12 = -6 |
||
|
2) -3(-2)(-6) = 6 (-6) = -36 |
9) Simplify: 2x + 3 + 5x - 8 = (2x + 5x) + (3 - 8) = 7x - 5 |
||
|
3) -8 + 2 = -6 |
10) Simplify: 5x - 2y Does not simplify--these are not like terms. |
||
|
4)
|
11) Simplify
|
||
|
5)
|
12) Solve 3w - 7 = 12 |
||
|
3w 3w w |
= 12 + 7 = 19 = 19/3 |
||
|
6) Simplify: 2(4x - 3) = 8x - 6 |
13)
|
||
|
7) Solve: 5b = -29
|
14) -12 - 4 = -16 |
||
|
15) Find the area of a triangle with a height of 12cm and a base of 5cm. (Use Use H = 12 and B = 5. Then A = Note that area is measured in square units (cm times cm = cm2) |
Problems 16-19 are worth 5 points each. Show all work necessary for the rest of the exam. Partial credit will be given for correct work only as shown on the exam paper.
|
16) Evaluate 3xy - 4x + 2 when x = -2 and y = 3. = 3(-2)(3) - 4(-2) + 2 = -18 + 8 + 2 = -8 |
||
|
17) Solve: 5x - 4 = 2x - 7 First, subtract 2x from each side: Then add 4 to each side: Then divide both sides by 3: |
3x - 4 = -7 3x = -3 x = -1 |
|
|
18) Solve: 2(2x - 1) = 7(x + 5) Multiply through parentheses: Subtract 4x from both sides: Subtract 35 from both sides: Divide by 3: |
4x - 2 = 7x + 35 -2 = 3x + 35 -37 = 3x x = |
|
|
19) Solve: 5 - 2(3x - 8) = 4x - 9 Multiply through parentheses: Combine like terms: Subtract 4x from both sides: Subtract 21 from both sides: Divide by -10: |
5 - 6x + 16 = 4x - 9 -6x + 21 = 4x - 9 -10x + 21 = -9 -10x = -30 x = 3 |
|
Go on to Lesson 6.
, where B is the base and H is the height)
= 30 cm2